Question

How many times does the digit 5 occur in tens place in the natural numbers from 100 to 1000
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Answer 1

Answer:

Hence, the digit 5 appears 271 times from 1 to 1000.

Step-by-step explanation:

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Answer 2

Given :-

The Number from 100 to 1000

To Find :-

How many times does the digit 5 occur in tens place in the natural numbers from 100 to 1000

Solution :-

First term = 105

Common difference = 5

Last term = 995

nth term = a + (n - 1)d

995 = 105 + (n - 1)5

995 - 105 = 5(n - 1)

890 = 5(n - 1)

890/5 = n - 1

165 = n - 1

165 + 1 = n

166 = n