Question

How many times does the electron go round the first bohr orbit of hydrogen in one second?

Answer 1

Hey dear,

◆ Answer-
6.622×10^15 Hz

◆ Explaination-
# Required values-
v = 2.2×10^6 m/s
r = 5.287×10^-11 m

# Solution-
Frequency of the electron in 1st Bohr's orbit is given by-
f = v / 2πr
f = (2.2×10^-6) / (2×3.142×5.287×10^-11)
f = 6.622×10^15 Hz

The electron will go round the orbit 6.622×10^15 times in one second.

Hope this helps...

Answer 2

Answer:The electron will go round 6.57 * 10^15 times in one second.

Explanation: We know, The relation of time period of electron for nth orbit is

T = T(not) * n^3

where T(not) = 1.51 * 10^-16 s.

Thus, for n=1,

T = 1.51 * 10^-16 s.

Now, frequency (f) = 1/T

Therefore,

f = 1/(1.51 * 10^-16)

f = 6.57 * 10^15 s^-1

Hope it helped.