How many times must a man toss a fair coin so that the peobability of having atleast one head is more than 90?
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answer : 180
Step-by-step explanation:
probability when tossed once
no. of favorable outcome = 1 head
total no. of outcomes = 2
p = 1/2
Let x be the times a man should toss a coin to have head at least more than 90
x *1/2 =90
x=90*2
x =180
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