Question

How many times must a man toss a fair coin so that the probability of having at least one head is more than 90%? please elaborate and give answer with all formulas used
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Answer 1

let it x be the number of heads.

coin toss is Bernoulli trial

P equal probability of head equal one by two.

Q=1-p

=1-1/2

After solving by the equation,

P(x=x) =nCx(1/2)n

P(x is greater than or equal to 1)

Greater than 90%

After solving this,

2n is greater than 10

N is greater than or equal to 4