how many times will factor 7 occur if the number 24500 is expressed as the product of prime factor
Answers
Answered by
2
Answer:
ANSWER
We have
N=24500
=100×245=100×5×49
=(5)
2
×(2)
2
×(7)
2
=(2)
2
×(5)
2
×(7)
2
Now
(i) No. of ways by which N cam be resolved into two factors =
2
1
[(2+1)(3+1)(2+1)]
=
2
1
×3×4×3=18
again
5N=(2)
2
×(5)
4
×(7)
2
No. of ways by which 5N by which can be resolved into two factors =
2
1
[(2+1)(4+1)(2+1)+1]
=
2
1
[3×5×3+1]
=
2
46
=23
Hence, the find the required answer.
Answered by
2
Answer:2 times
Step-by-step explanation:
24500=7×7×5×5×5×2×2
So 24500 can be expresssed as product of these factors.
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