Math, asked by prabakaran32354, 10 months ago

how many times will factor 7 occur if the number 24500 is expressed as the product of prime factor ​

Answers

Answered by rudra1981sharma
2

Answer:

ANSWER

We have

N=24500

=100×245=100×5×49

=(5)

2

×(2)

2

×(7)

2

=(2)

2

×(5)

2

×(7)

2

Now

(i) No. of ways by which N cam be resolved into two factors =

2

1

[(2+1)(3+1)(2+1)]

=

2

1

×3×4×3=18

again

5N=(2)

2

×(5)

4

×(7)

2

No. of ways by which 5N by which can be resolved into two factors =

2

1

[(2+1)(4+1)(2+1)+1]

=

2

1

[3×5×3+1]

=

2

46

=23

Hence, the find the required answer.

Answered by maddulamounika111
2

Answer:2 times

Step-by-step explanation:

24500=7×7×5×5×5×2×2

So 24500 can be expresssed as product of these factors.

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