Computer Science, asked by paltamanna123, 8 months ago

How many times will the following loop execute? What will be the final

output?

int z = l;

while(z < 10)

if(z++ % 2 == 0)

System.out.println(z);​

Answers

Answered by shravanisagare
4

Answer:

class q1a{

public static void sumUp(int n, int total){

int i;

for (i=1; i<=n; i++){

total = total +i;

}

}

public static void main(String args[]){

int n, total;

n=10; //n can be initialized to any +ve number

total=0;

sumUp(n, total);

System.out.println(total);

Explanation:

Reason: Method sumUp does not return any

value. The change in the local variable total is

not visible outside the method. Reason:

- Initially an object is created which is referred by q

and has instance variables p=10 and q=66.

- When method origin1() is invoked the parameter p

starts referring to the object referred by q. However,

p=new point(0,0) creates a new object (instance

variables p=0, q=0), and p starts referring to the new

object. Since, p is a local variable, any change to p is

not visible outside the method. Therefore, instance

variables of q do not change

- q.printpoint(), therefore, prints values of instance

variables of q which are 10 and 66

- method origin2() is invoked and parameter p starts

referring to object referred by q. Through use of p

instance variables of object referred by q, are

modified. The change is done in the object itself.

Hence, instance variables of the object change to p=15

and q=20.

- q.printpoint() prints values of instance variables of q

which are now 15 and 20.

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