How many times will the rate of the reaction 2A+B---> A2B change if the concentration of substance A is doubled and that of B is halved????
Answers
Hi,
Answer:
The rate of reaction will changes 2 times.
Explanation:
Given data:
Equation of reaction: 2A + B ↔️ A₂B
The concentration of A is doubled
The concentration of B is halved
To find: no. of times the rate of reaction will change
We know that the expression for the rate of reaction is given by
R = K [A]² [B] ..... (i)
where, K is the equilibrium constant
Now, we have
New [A] = [2 * A] .... (ii)
New [B] = [½ * B] ..... (iii)
Therefore,
New R = K * New [A]² * New [B]
substituting the values from (i) & (ii), we get
New R
= K [2 * A]² [½ * B]
= K * 4 * [A]² * ½ * [B]
= 2 * K [A]² [B] …… (iv)
Hence, from equation (i) & (iv) we can conclude that, after the concentration of A is doubled and B is halved the rate of reaction increases by 2 times.
Hope this helps!!!!!