How many total atoms are in 0.410 g of P2O5?
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1 mol of P2O5 = (2+5) atoms *6,022*10^23= 42,154*10^23 atoms
1 mol of P2O5= 2*30,97g+5*16g=141,94g
1mol : xmol= 141,94 g : 0,400g
=> 0,400g= 0,0028 mol
1 mol : 42,154*10^23 atoms = 0,0028 mol : x atoms
=> 0,0028 mol = 1,180*10^22
DC
1 mol of P2O5= 2*30,97g+5*16g=141,94g
1mol : xmol= 141,94 g : 0,400g
=> 0,400g= 0,0028 mol
1 mol : 42,154*10^23 atoms = 0,0028 mol : x atoms
=> 0,0028 mol = 1,180*10^22
DC
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