Question

How many triangles can be drawn by means of 9 non collinear points?

Answer 1

Answer:

85

Step-by-step explanation:

$\sqrt[ \times 3 \sqrt{1 \sqrt{ > \sqrt{5 {20.551426554551215 \frac{1 \frac{ \sqrt[gcg]{?} }{?} }{?} }^{?} } } \times \frac{?}{?} } \times \frac{?}{?} ]{?}$

Answer 2

84 triangles can be drawn by means of 9 non-collinear points.

Given:

9 non-collinear points.

To Find:

We have to find how many triangles can be drawn by means of 9 non-collinear points.

Solution:

This is a simple problem from permutation and combination.

Let us tackle this problem.

We can quickly solve this problem as follows,

We know, that we need 3 non-collinear points to draw a triangle.

Therefore, we have to take up 3 non-collinear points from 9  non-collinear points.

Now,

We can choose 3 non-collinear points from 9  non-collinear points in 9C3 ways.

Now, we calculate the value of 9C3.

$9C3=$ $\frac{9!}{3!*(9-3)!}$

=$\frac{9!}{3!*6!}$

=$84$

Hence, 84 triangles can be drawn by means of 9 non-collinear points.

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