how many triangles can be drawn with one side 6 cm and perimeter 15 cm with other two sides as natural numbers
Answers
Answer:
56 triangle in the shape
Given :- How many triangles can be drawn with one side 6 cm and perimeter 15 cm with other two sides as natural numbers ?
Solution :-
Let other two sides be a and b .
so,
→ Perimeter = 15 cm
→ One side = 6 cm
→ 6 + a + b = 15
→ a + b = 15 - 6 = 9 .
now, we know that,
- sum of any two side of ∆ > Third side .
- Difference between any two sides < Third side.
then,
→ a + b > 9 and a - b < 6
checking possible values with these two conditions we get,
if a and b are 1 , 8 or 8 , 1
- 6 + 1 + 8 = 15
- 6 + 1 < 8
Side are not possible Possible .
if a and b are 2 , 7 or 7 , 2
- 6 + 2 + 7 = 15
- 6 + 2 > 7 , 2 + 7 > 6 , 7 + 6 > 2 .
- 6 - 2 < 7 , 7 - 2 < 6 , 7 - 6 < 2 .
- Side are Possible .
if a and b are 3 , 6 or 6 , 3
- 6 + 6 + 3 = 15
- 6 + 3 > 6 , 6 + 6 > 3
- 6 - 3 < 6 , 6 - 6 < 3
- Side are Possible .
if a and b are 4 , 5 or 5 , 4
- 4 + 5 + 6 = 15
- 4 + 5 > 6 , 5 + 6 > 4 , 4 + 6 > 5 .
- 5 - 4 < 6 , 6 - 5 < 4 , 6 - 4 < 5 .
- Side are Possible .
therefore, we can conclude that , total 3 triangles with sides as (6,2,7) , (6,3,6) and (6,4,5) can be draw with other two sides as natural numbers .
Learn more :-
Diagonals AC and BD of quadrilateral ABCD meet at E. IF AE = 2 cm, BE = 5 cm, CE = 10 cm, 8 सेमी.
brainly.in/question/27312677
Let abcd be a rectangle. the perpendicular bisector of line segment bd intersect ab and bc in point e and f respectively...
brainly.in/question/27813873