Question

How many triplets x,y,z satisfies the equation x+y+z=6 where x,yand z are the natural number.

Answer 1

Step-by-step explanation:

Given  

How many triplets x,y,z satisfies the equation x+y+z=6 where x,y and z are the natural number.

So we need to find the triplets that is 3 numbers satisfying x + y + z = 6. So the numbers are

4   1     1

1    4    1

1    1    4

1    2    3

1    3    2

3     1   2

3     2    1

2     3     1

2     1     3

2     2     2

So the number of triplets will be 10

Answer 2

There are 10 triplets of x,y,z satisfies the equation x+y+z=6.

Step-by-step explanation:

To find : How many triplets x,y,z satisfies the equation x+y+z=6 where x,y and z are the natural number ?

Solution :

We want the three numbers whose sum is 6 the possible numbers are from 1,2,3,4.

Like If let x=1, y=2 and z=3 then 1+2+3=6

Similarly taken according to order the patters were,

(4,1,1) (1,4,1) (1,1,4) (1,2,3) (1,3,2) (3,1,2) (3,2,1) (2,3,1) (2,1,3) (2,2,2)

Therefore, there are 10 triplets of x,y,z satisfies the equation x+y+z=6.

#Learn more

The number of triplets (x, y, z) of positive integers satisfying 2^x+2^y+2^z=2336 is​

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