Question

how many triplets (x,y,z) satisfy the equation x+y+z=6 where x,y,z are natural numbers?​

Answer 1

Answer:

Step-by-step explanation:

There are 10 triplets of x,y,z satisfies the equation x+y+z=6.

Step-by-step explanation:

To find : How many triplets x,y,z satisfies the equation x+y+z=6 where x,y and z are the natural number ?

Solution :

We want the three numbers whose sum is 6 the possible numbers are from 1,2,3,4.

Like If let x=1, y=2 and z=3 then 1+2+3=6

Similarly taken according to order the patters were,

(4,1,1) (1,4,1) (1,1,4) (1,2,3) (1,3,2) (3,1,2) (3,2,1) (2,3,1) (2,1,3) (2,2,2)

Therefore, there are 10 triplets of x,y,z satisfies the equation x+y+z=6.

The number of triplets (x, y, z) of positive integers satisfying 2^x+2^y+2^z=2336 is​