How many tudo digit numbees.
leave the remaindet zwhen divided
by 10?
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6
Answer:
Of all the 2-digit numbers that have a remainder of 1 when divided by 10, only 11, 11 + LCM(6, 10) = 11 + 30 = 41, and 41 + 30 = 71, when divided by 6, yield a remainder of 5.
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