Question

how many two digit multiples are there of 3
Arithmatic progressions​

Answer 1

Step-by-step explanation:

We know, first two digit number divisible by 3 is 12 and last two digit number divisible by 3 is 99. Thus, we get

12,15,18,...,99 which is an AP

Here, a=12,d=3

Let there be n terms. Then,

a

n=99

a+(n−1)d=99

12+(n−1)3=99

n=29+1=30

Therefore, two digit numbers divisible by 3 are 30.

Answer 2

Answer:

33 is answer

Step-by-step explanation:

divide 99 from 3 answer will be 33