How many two digit no. Are divisible by 6?
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chahatsharma5759:
Thankiuuu sOoo much for answering my question.....m
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To find two digit numbers that are divisible by 6
By Divisibility rule,
6 is a multiple of 2 and 3.
Thus it has two combination to test ie; Test for 2 and Test for 3.
The first two digit number divisible by 6 is 12 and
The last two digit divisible by 6 is 96
Let a=12 , d=6, an=96
Now we have
an=a+(n-1)d
=>96=12+(n-1)6
=>96-12=(n-1)6
=>84=(n-1)6
=>n-1=84 / 6
=>n-1=14
=>n=14+1
=>n=15
Hence total number of two digit number divisible by 6 = 15.
By Divisibility rule,
6 is a multiple of 2 and 3.
Thus it has two combination to test ie; Test for 2 and Test for 3.
The first two digit number divisible by 6 is 12 and
The last two digit divisible by 6 is 96
Let a=12 , d=6, an=96
Now we have
an=a+(n-1)d
=>96=12+(n-1)6
=>96-12=(n-1)6
=>84=(n-1)6
=>n-1=84 / 6
=>n-1=14
=>n=14+1
=>n=15
Hence total number of two digit number divisible by 6 = 15.
only 15 no
Thanks
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