Question

How many two digit number have their square ending with 8?

Answer 1

Answer:13

Step-by-step explanation:

Answer 2

Answer: There is no any two digit number whos square is ending with 8.

Explanation:As we know that all the perfect square number ends with 0,1,4,5,6 and 9.

For example:

The square of 1 is 1.

i.e.     $1^{2} = 1$×$1=1$

The square of 2 is 4.

i.e.    $2^{2}=2$×$2=4$

The square of 3 is 9.

i.e.    $3^{2}= 3$×$3=9$

The square of 4 is 16.

i.e.    $4^{2}=4$×$4=16$

The square f 5 is 25.

i.e.    $5^{2}=5$×$5=25$

The square of 6 is 36.

i.e.    $6^{2}=6$×$6=36$

The square of 7 is 49.

i.e.   $7^{2}=7$×$7=49$

The square of 8 is 64.

i.e.   $8^{2}=8$×$8=64$

The square of 9 is 81.

i.e.   $9^{2}=9$×$9=81$

The square of 10 is 100.

i.e.   $10^{2}=10$×$10=100$

and so on......

Hence,There is no any two digit number whos square is ending with 8.

A perfect square is a type of number that can be expressed as the product of any integer by itself or as the second exponent of any integer. For example, 49 is a perfect square because it is the product of integer 7 by itself is 7 × 7 = 49. However, 19 is not a perfect square number because it cannot be expressed as the product of two same integers.

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