Question

how many two digit numbera are divisibe by 3​

Answer 1

Step-by-step explanation:

First two digit number divisible by 3 = 12

Last two digit number divisible by 3 = 99

An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant.

A.P = 12,15,18,…,99

here

First term (a) = 12

Common difference (d) = 3

Let us consider there are n numbers then

an = 99a + (n – 1)d = 9912 + (n – 1)3 = 9912 + 3n – 3 = 99n = 29+1n = 30

∴ Two digit numbers divisible by 3 = 30.