Question

How many two-digit numbers are divisible by 3 ?​

Answer 1

Given:-

• A number is given to us.
• The number is 3.

To Find:-

• The total number of 2 digit number divisible by 3.

Formulae Used:-

• To find nth term of a series :

$\large\underline{\boxed{\red{\tt{\dag T_n =a+(n-1)d}}}}$

where ,

• a is first term.
• n is the required term.
• d is common difference

Answer:

Here it's given a number 3 and we are asked to find total number of 2-digit number divisible by 3.

The concept here we will use is of "Arthemetic Progressions " .

Now the first two digit number divisible by 3 is 12.

And before 100 , 99 is divisible by 3 .

So , the series will look something like this :—

• 12,15,18,21,..............,99.

Here

• First term is 12 (a).
• Last term is 99. $\sf{T_n}$
• Common difference is 3. (d).

As per the above formula mentioned , let's put the respective values :-

$\sf{\implies T_n = a+(n-1)d.}$

$\sf{\implies 99 = 12+(n-1)3.}$

$\sf{\implies 99-12=(n-1)3.}$

$\sf{\implies 87=(n-1)3.}$

$\sf{\implies (n-1)=\dfrac{87}{3}.}$

$\sf{\implies n-1=23}$

$\bf{\leadsto n = 24.}$

Hence the required answer is 24.

Answer 2

"acceleration is the rate of change of velocity per unit time.it is a vector quantity