Math, asked by Garvit100, 1 year ago

How many two-digit numbers are divisible by 3? (Solve it by the formula of arithmetic progression).

Answers

Answered by NishantShandilya
1
Heyy its me NISHANT MISHRA!!
SOLUTION:



AP:3,6,9........99

a=3
d=3
last term=99

let the no. of terms be n then,

a+(n-1)d=99
3+(n-1)3=99
(n-1)3=96
(n-1)=32
n=33

no. of two digit no. =33


hope it hepl!!
Similar questions