How many two-digit numbers are divisible by 3? (Solve it by the formula of arithmetic progression).
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Heyy its me NISHANT MISHRA!!
SOLUTION:
AP:3,6,9........99
a=3
d=3
last term=99
let the no. of terms be n then,
a+(n-1)d=99
3+(n-1)3=99
(n-1)3=96
(n-1)=32
n=33
no. of two digit no. =33
hope it hepl!!
SOLUTION:
AP:3,6,9........99
a=3
d=3
last term=99
let the no. of terms be n then,
a+(n-1)d=99
3+(n-1)3=99
(n-1)3=96
(n-1)=32
n=33
no. of two digit no. =33
hope it hepl!!
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