Question

how many two digit numbers are divisible by 3? solve using the concept of AP
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Answer 1

Answer:

we what to draw so i cant ok bro

Answer 2

Step-by-step explanation:

first 2 digit number divisible by 3 = 12

second 2 digit number divisible by 3 = 15

last 2 digit number divisible by 3 = 99

common difference (d) = 3

AP = 12,15,18..........99

using formula Tn = a+(n-1)d

99 = 12 + (n-1)3

99-12 = 3n-3

87+3= 3n

n = 90/3

n = 30

2 digit numbers divisible by 3 = 30