How many two digit numbers are divisible by 4?
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Answered by
3
Condition for being divisible by 4:
Numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4.
For example, the number formed by the last two digits of the number 3628 is 28, which is evenly divisible by 4 so the number 3628 is evenly divisible by 4.
lets try for two digit numbers :
(a)10 :Number formed by last two digit is 10 itself which is obviously not divisible by 4 as is gives remainder 2
(b) 11 : Number formed by last two digit is 11 itself which is obviously not divisible by 4 as it gives remainder 3
(c) 12: Number formed by last two digit is 12 itself which is obviously divisible by 4 as is gives remainder 0.
Hence, the required answer is 12.
Hope it helps.
I hope this will help you
Numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4.
For example, the number formed by the last two digits of the number 3628 is 28, which is evenly divisible by 4 so the number 3628 is evenly divisible by 4.
lets try for two digit numbers :
(a)10 :Number formed by last two digit is 10 itself which is obviously not divisible by 4 as is gives remainder 2
(b) 11 : Number formed by last two digit is 11 itself which is obviously not divisible by 4 as it gives remainder 3
(c) 12: Number formed by last two digit is 12 itself which is obviously divisible by 4 as is gives remainder 0.
Hence, the required answer is 12.
Hope it helps.
I hope this will help you
Answered by
41
using AP
12,16,20....96
Tn=a+(n-1)d
96=12+(n-1)4
(96-12)÷4=n-1
84÷4=n-1
21=n-1
21+1=n
22=n
12,16,20....96
Tn=a+(n-1)d
96=12+(n-1)4
(96-12)÷4=n-1
84÷4=n-1
21=n-1
21+1=n
22=n
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