how many two digit numbers are there which 31/394 end in 7 , divisible by 3
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We know, first two digit number divisible by 3 is 12 and last two digit number divisible by 3 is 99. Thus, we get
12,15,18,...,99 which is an AP
Here, a=12,d=3
Let there be n terms. Then,
a
n
=99
a+(n−1)d=99
12+(n−1)3=99
n=29+1=30
Therefore, two digit numbers divisible by 3 are 30.
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