Question

How many two digit numbers can be formed using 3,3,5,5,7,7. basically i wanted to solve this (how many two digit numbers can be formed using 3,5,7 repetation is allowed) but in a different way, so can we solve it( the question i had formed) using nPr when objects are alike or we cant?

Answer 1

Answer:

Solution

The given digits are 3,7,9 and repetition of digits is allowed.

Out of the given digits, the possible ways of choosing the two digits are

3,7;3,9;7,9

Using the digits 3 and 7, the n numbers are

37,73,33 and 77.

Similarly, Using the digits 3 and 9, the numbers are 39,93, and 99.

Using the digits 7 and 9, the numbers are 79 and 97.

Hence, all possible 2−digit numbers are

37,73,33,77,39,93,99,79,97

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Answer 2

Actually it is same as when repetition is allowed,you can add million's of 3,5,7 but it won't matter.