Question

How many two-digit numbers can you
come up with in which the tens are greater

than the ones?

Answer 1

Answer:

Step-by-step explanation:

Let the two no.s be a,b

Given,  

a>b

(a+b)=2(a−b)

⟹a=3b

Put values of b such that a<10 (otherwise it would be a 3 digit number)

b=1,2,3

a=3,6,9

So, the possible numbers are 31,62,93.

Hence, 3 such numbers are possible.

please mark as brainliest

Answer 2

Answer:

This is a rather simple problem involving one equation, and one inequality.

Let our number have the tens digit as xx and units digit yy .

Our first condition:

x>yx>y

Our second:

x+y=2(x−y)x+y=2(x−y)

Simplifying…

x+y=2x−2yx+y=2x−2y

2x−x=y+2y2x−x=y+2y

x=3yx=3y

So, now we substitute values for yy to find corresponding values of xx .

Note that xx will always be greater than yy because we assumed this when doing x−yx−y .

I'm going to list out all our possible 2 digit numbers. Writing xx and yy again and again on a phone is getting painful.

31,62,9331,62,93

Anything larger than 3 for the units digit gives a 3 digit number.

So there you go, 3 possible solutions.