.how many two digit numbers increase by 18 when their digits are reversed?
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An equation in 2 variables can be obtained for this.
Assume that the digits of the 2 digit number are 'x' and 'y'.
The 2 digit number is represented as: 10x + y [In the example you have given, x=1 and y=3, therefore, it can be represented as 10(1) + 3 = 13]
It is also given that on adding 18 to the given number, the digits are reversed. Representing that in the form of a linear equation:
10x + y + 18 = 10y + x [RHS = Digits are reversed]
9x - 9y = -18
x - y = -2
=> y - x = 2
Substitute values for x and y such that the above equation is satisfied.
On substituting values for x and y, we get the following numbers which when increased by 18, get their digits reversed:
24, 35, 46, 57, 68, 79
Hope it will help u if u have any query plz cmt
Assume that the digits of the 2 digit number are 'x' and 'y'.
The 2 digit number is represented as: 10x + y [In the example you have given, x=1 and y=3, therefore, it can be represented as 10(1) + 3 = 13]
It is also given that on adding 18 to the given number, the digits are reversed. Representing that in the form of a linear equation:
10x + y + 18 = 10y + x [RHS = Digits are reversed]
9x - 9y = -18
x - y = -2
=> y - x = 2
Substitute values for x and y such that the above equation is satisfied.
On substituting values for x and y, we get the following numbers which when increased by 18, get their digits reversed:
24, 35, 46, 57, 68, 79
Hope it will help u if u have any query plz cmt
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