Math, asked by bunny9548, 11 months ago

How many two digit numbers leave the remainder 1 when divided by 5?

Answers

Answered by kurmaminu
2

Answer:

19 numbers

Step-by-step explanation:

the numbers are 6,11,16,21,26,31,36,41,46,51,56,61,66,71,76,81,86,91,96

Answered by aakankshach2203
10

Answer:

Step-by-step explanation:

The two digit numbers are:

11,16,21,26,.......,96.

Let,

a=11

t2=16

t3=21

tn=96

Now,

t2 - a = 16- 11 = 5

t3 - t2 = 21 - 16 = 5

Thus, the numbers are in A.P. where d=5.

tn = a + (n-1) d

96 =11 + (n-1) d

85 = 5n - 5

90 = 5n

n = 18.

The number of 2 digit numbers is 18

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