How many two-digit numbers leave the remainder 1 when
divided by 5? Find the sum of all these numbers.
Answers
Answer:
912
Step-by-step explanation:
A number which is divisible by 5 ends in either 5 or 0. So we must add one to these values to end up with 6 or 1.
1 can not be divided by 5 unless it with decimals, so we can expel 1 from our two-digit number list, which is as follows:
6,11,16,21,26,31,36,41,46,51,56,61,66,71,76,81,86,91,96
Adding these together we obtain 912.
Answer:
11+16+21+26+31+36+41+46+51+56+61+66+71+76+81+86+91+96=903
Step-by-step explanation:
While answering, look for the patterns. Like here, the number giving remainder 1 when divided by 5 is always 1 greater than the number divisible by 5 e.g 10 os divisible by 5 but 11 gives the remainder of 1. Similarly 15 is divisible by 5 but 16, which is one greater than 15, gives a remainder of 1 when divided by 5.