Question

how many two digit numbers leave the remainder 1 when divisible by 5​

Answer 1

• There are 18 numbers that leave the remainder 1 when divided by 5

Answer 2

Answer:

Let x is at 10’s place and y at 1′ place

then 10x+y=5n+1

y=5n-10x+1

y=5(n-2x)+1

As y is positive number

so y=5q+1 ( where q=n-2x is a positive integer)

Now max value of y is 9

so q=0 or 1

and y=1 or 6

Thus all the 2 digit numbers with 1 or 6 at 1’s place will satisfy the situation

S no are 11,21,31…………………………………91

and 16,26,……………………………………………..96

Total 18 numbers are possible

Step-by-step explanation:

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