Question

How many two digits numbers can be divosible by 3 ?
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Answer 1

Answer:

So, the A.P. will be 12, 15, 18, 21, ………….99 We need to find n Last term of this series is 99 So, an = 99 & a = 12d = 15 – 12 = 3 Now, an = a + (n – 1) d Putting values 99 = 12 + (n – 1) (3) 99 = 12 + 3n – 3 99 = 9 + 3n 3n = 99 – 9 3n = 90 n = 90/3 = 30 Therefore , there are 30 two digit numbers divisible by 3

Answer 2

Answer:

There are 30 two digit no.s divisible by 3

Step-by-step explanation:

12,15,18,.....,99 is an AP

n terms of ap = a + (n-1)d

12 + (n-1)3=99

12 + 3n - 3=99

3n=90

n=30