how many two input NAND gates are required to perform the action of a two input OR gate?
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We can use 3 NAND gates to perform the action of an OR gate.
We first use 2 NAND gates, and their outputs are connected to the third NAND gate, which then produces the same result as an OR gate.
If X is the initial input in the first NAND gate, we get
(X.X)`
= X`
If Y is the initial input in the second NAND gate, we get
(Y.Y)`
= Y`
When we connect these two outputs to the input of the third NAND gate, we get
(X` . Y`)`
= (X`)` + (Y`)`
= X + Y
which is an OR gate.
We first use 2 NAND gates, and their outputs are connected to the third NAND gate, which then produces the same result as an OR gate.
If X is the initial input in the first NAND gate, we get
(X.X)`
= X`
If Y is the initial input in the second NAND gate, we get
(Y.Y)`
= Y`
When we connect these two outputs to the input of the third NAND gate, we get
(X` . Y`)`
= (X`)` + (Y`)`
= X + Y
which is an OR gate.
ChetanRA:
There is an issue with the formatting of the answer, kindly bear with me while I get it sorted out.
It is now sorted.
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