Question

how many types of gametes are formed from pea plant having genotype YyRr?a)1 b)2 c)3d4​

Answer 1

Answer:

Two types

Explanation:

The plant having genotype AABbCC is heterozygous for only one character B. Number of "gametes = 2n", where n is the heterozygosity." Since n = 1 so 2 gametes will be formed. Those are ABC and AbC. So the two types of gametes will be ABC and AbC.

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Answer 2

Total possible gametes formed by a genotype is = 2 n

where n is a number of genes for which it is heterozygous. The given genotype VVRRtt is homozygous for all three genes; thus it will form only one type of all gametes carrying “VRt”. As we know that dihybrid plant is heterozygous for two genes, thus total possible gametes by it = 2²

= 4. Similarly, trihybrid and tetrahybrid plants are heterozygous for three and four genes respectively, thus total possible gametes = 2³ and

2^4 = 8 and 16 respectively. A plant heterozygous for one gene makes two types of gametes; 2 1

= 2. The correct option is D.