Question

how many types of gametes are possible with the genotype Bbcc? write the percentage of getting the gamete bc​

Answer 1

Answer:

No. of homologous chromosome pairs (heterozygous genes) No. of different gametes from each parent

1 (Aa X Aa) 2 (21)

2 (AaBb X AaBb) 4 (22)

3 (AaBbCc X AaBbCc) 8 (23)

4 (AaBbCcDd X AaBbCcDd) 16 (24)

Answer 2

Answer:

AaBbCC will produce 4 types of gametes which are as follows- ABC, AbC, aBC, abC. The number of gametes formed is decided by the number of heterozygous alleles present in the given genotype. 2^n is the formula used to find it out, where n=number of heterozygous alleles present in the genotype. Say for example, in the above genotype Aa & Bb are the 2 heterozygous alleles, so here n=2. Putting the values in the formula , we get 2^2=4. Hence 4 types of gametes are formed.

So the correct option is 'four'.