Question

how many types of length and breadth 12 cm and 8 cm, respectively, are needed to cover a rectangular region of length and breadth 5 metre 20 cm and 1 m 40 cm, respectively?
ANSWER-759 tiles​

Answer 1

Answer:

759 tiles

Step-by-step explanation:

Fri and sat down to the breastbone to the breastbone

Answer 2

${\large{\frak{\green{\dag{\underline{\underline{Given:}}}}}}}$

• Length and breadth of a rectangular tile are 12cm & 8cm respectively
• Length and breadth of a rectangular region are 5m20cm & 1m40cm respectively

${\large{\frak{\orange{\dag{\underline{\underline{To Find:}}}}}}}$

• No. of tiles of length 12cm and breadth 8cm are needed to cover a rectangular region of length 5m20cm and breadth 1m40cm

${\large{\frak{\blue{\dag{\underline{\underline{Solution:}}}}}}}$

• Length of tile = 12cm
• Breadth of tile = 8cm

We, know that area of rectangular tile = l × b

where ,

• l = length = 12cm
• b = breadth = 8cm

${\implies{\small{\tt{Area\ of\ tile = 12cm × 8cm = 96cm²}}}}$

• Length of rectangular region = 5m 20cm
• = (5×100)cm + 20cm
• = 500cm + 20cm
• = 520cm

• breadth of rectangular region = 1m40cm
• =( 1 × 100)cm + 40cm
• = 100cm + 40cm
• = 140cm

Area of rectangular region = l × b

where,

• l = length = 520cm
• b = breadth = 140cm

${\implies{\small{\tt{Area\ of \ rectangular\ region = 520cm × 140cm = 72800cm²}}}}$

• No. of tiles needed are = 72800/96
• No. of tiles needed = 758.3333
• No. of tiles needed = 759 tiles

${\small{\underline{\boxed{\frak{\red{\therefore \ no. \ tiles \: required \: are \: 759 \: tiles}}}}}}$