Question

how many types of length and breadth 12m and 8 cm, respectively are needed to cover a rectangular region of length and breadth 5 metre 20 cm and 1 metre 40 cm, respectively?
Answer- 759 tiles​

Answer 1

Answer:

it can be found by

area of big region \ area of small region

that is

520×140\12×8

= 758.88 tiles

= 759 approx

and there will be 12 cm

not 12 m

Answer 2

Step-by-step explanation:

Area of region = 100 cm x 144 cm = 14400 cm.sq

Area of one tile = 5 cm x 12 cm = 60 cm.sq

Number of tiles = \frac{Area\ of\ region}{Area\ of\ one\ tile}

Area of one tile

Area of region

= 240

Thus, 240 tiles are required.

(b) Area of region = 70 cm x 36 cm = 2520 cm.sq

Area of one tile = 5 cm x 12 cm = 60 cm.sq

Number of tiles = \frac{Area\ of\ region}{Area\ of\ one\ tile}

Area of one tile

Area of region

= 42

Thus, 42 tiles are required.