How many unit cells are present in a cube shaped ideal crystal of nacl of mass 1 g?
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Answered by
5
One unit cell of Nacl contains 4 Nacl units and haa mass=
(4×58.5)÷(6.023×10^23) grams
No. of unit cell in 1 gram=
(6.023×10^23)÷(4×58.5)
=2.57 ×10^21
(4×58.5)÷(6.023×10^23) grams
No. of unit cell in 1 gram=
(6.023×10^23)÷(4×58.5)
=2.57 ×10^21
Answered by
2
Answer: 2.57 × 10^ 21 unit cells
Explanation:
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