How many units will consume an induction motor of capacity 7.5 hp mptpr?
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If the motor is fully loaded, it will provide output power of 3HP = (3 X 0.746) kW = 2.24 kW. Unit consumed = Power in kW X numbers of hours of operation. Hence units burnt (consumed) by 3 HP motor in 24 hours will be 59.76, if the motor efficiency is 90% and motor is fully loaded.
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