Question

How many unpaired electrons are present in the ground state of Fe3+ (Z = 26), Mn2+(Z=25) , Ar (Z=18) and Cr(Z=24).​

Answer 1

Answer:

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Explanation:

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Answer 2

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Explanation:

(I) Fe → Fe3+ + 3e-

Fe (Z = 26)

Fe3+ = number of electrons = 23

1s2 2s2 2p6 3s2 3p6 3d6 4s2 for Fe atom.

1s2 2s2 2p6 3s2 3p6 3d5 for Fe3+ ion.

So, it contain 5 unpaired electrons.

Mn (Z = 25) Electronic configuration is

1s2 2s2 2p5 3s2 3p6 4s2 3d5

Mn → Mn2+ + 2e-

Number of unpaired electrons in Mn2+ = 5 Ar (Z = 18).

Electronic configuration is 1s2 2s2 2p6 3s2 3p6 All orbitals are completely filled. So, no unpaired electrons in it.