Question

How many values of x'exist for which p(x) = x2 - x + 2 has/have negative value/s?​

Answer 1

Answer: there is no value of x neither +ve nor -ve

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

p(x) = $x^2 - x +2 < 0$

No. the above equation cannot have negative values for x > 1 or x < -1 because $x^2$ is greater than x.

It cannot have any negative values if x ≤ 1 or x ≥ -1

because 2 will always be greater than $x^2$ - x