How many vibrations will a tuning fork of frequency 280 hz complete during the sound travels forward in aur by 20m?
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Speed of sound=340m/s
Distance=20m
Speed =distance/time
time=distance/speed
time=20/340
=0.05sec
Frequency=280Hz
Frequency= No.of Vibrations in one second=280Hz
Therefore number of Vibrations completed in 0.05sec
=280x0.05=14 Vibrations
Distance=20m
Speed =distance/time
time=distance/speed
time=20/340
=0.05sec
Frequency=280Hz
Frequency= No.of Vibrations in one second=280Hz
Therefore number of Vibrations completed in 0.05sec
=280x0.05=14 Vibrations
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