How many vibrations will a tuning fork of frequency 280hz complete during the time sound travels forward in air 20m. Take speed of sound in air as 340m/s.
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Speed of sound = 340m/s
Frequency = 280Hz
Distance = 20 m
We know,
Time = Distance/Speed
= 20 m/ 340 m/s
= 17 s
∴No. of vibrations completed in 17 s = 280 × 17
= 4760 ANS
Frequency = 280Hz
Distance = 20 m
We know,
Time = Distance/Speed
= 20 m/ 340 m/s
= 17 s
∴No. of vibrations completed in 17 s = 280 × 17
= 4760 ANS
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