Question

How many volume of cl is required to form 11.2l of hcl at 273k and 1atm pressure?

Answer 1

Hey there!

The equation will be:

H₂ + Cl₂ = 2 HCl

1 mole of chlorine gas is required to form 2 mole of HCl.

i.e 22.4 litres of chlorine is required to form 44.8 litres of HCl.

x litres of chlorine is required to form 11.2 litres of HCl.

x = (22.4 / 44.8) * 11.2

x = 22.4 / 4

x = 5.6

Hence, 5.6 litres of chlorine is required to form 11.2 litres of HCl.