Question

How many water molecules are present in 0.1 ml of h2o?

Answer 1

Answer:0.33*10^22

Explanation: given mass of water = 0.1 ml = 0.1g

no. of moles of water = 0.1/18 = 0.0055

no. of molecules of water = 0.0055*6.022*10^23 = 0.33*10^22

Answer 2

The number of molecules of water that are present is $3.31\times 10^{21}$

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 0.1 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{0.1mL}\\\\\text{Mass of water}=(1g/mL\times 0.1mL)=0.1g$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of water = 0.1 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

$\text{Moles of above}=\frac{0.1g}{18g/mol}=0.0055mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, 0.0055 moles of water will contain = $(0.0055\times 6.022\times 10^{23})=3.31\times 10^{21}$ number of molecules

Learn more about mole concept and number of moles:

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