Question

how many water molecules are present in 18 gram of water​

Answer 1

It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams. Since we only have 0.001 grams, that means that we have NA * (0.001/18) = 3.35*1019molecules of water!

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Answer 2

Hey mate

Your answer = 6.022x1023