how many water molecules will be last on the hydrating 0.684 gram of sucrose?
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Thus, from one molecule of sucrose, 11 molecules of water are removed. 0.684 g of sucrose corresponds to 0.684342=0.002 0.684 342 = 0.002 moles which on dehydration will give 0.002×11=0.022 0.002 × 11 = 0.022 moles of water.
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Answer:
Thus, from one molecule of sucrose, 11 molecules of water are removed. 0.684 g of sucrose corresponds to 0.684342=0.002 0.684 342 = 0.002 moles which on dehydration will give 0.002×11=0.022 0.002 × 11 = 0.022 moles of water.
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