How many ways are there to arrange a five digit number?
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And we know that permutation of ’n' different objects taken ‘r' at a time
= n(n-1)(n-2)……..(n-(r-1)) , which is denoted by nPr OR n! ( factorial n)
So, here, 5P5 = 5(5–1)(5–2)(5–3)(5–4)
= 5 * 4* 3 * 2 * 1 = 120
●ANS● in 120 ways, the given numbers can be arranged
= n(n-1)(n-2)……..(n-(r-1)) , which is denoted by nPr OR n! ( factorial n)
So, here, 5P5 = 5(5–1)(5–2)(5–3)(5–4)
= 5 * 4* 3 * 2 * 1 = 120
●ANS● in 120 ways, the given numbers can be arranged
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