Question

How many ways are there to put four different employees into three indistinguishable offices, when each office can contain no more than two employees?

Answer 1

Answer:

Mark my answer as BRAINLIEST

Here offices are identical

We can put 4 employees into 1 office in 1 way ⇒ [ 4C4 = 1]

OR

We can put 3 employees into 1 office & 1 employee into another office in 4 ways ⇒ [ 4C3 = 4]

OR

We can put 2 employees into 1 office and 1 employee into another office and remaining 1 employee into another office in 6 ways ⇒ [ 4C2 = 6]

OR

We can put 2 employees into 1 office and 2 employees into another office in 3 ways ⇒ [ 4C22 = 62 = 3]

So, total no. of ways = 1 + 4 + 6 + 3 = 14 ways