Question

How many ways can 2700 be written as a product of 8 distinct integers?

Answer 1

I don't know it you must search it on internet search

Answer 2

First of all factorise 2700.

After factorising we get 2700= 2*2*3*3*3*5*5*1

but these numbers not distinct numbers after some rearrangement we can make it as a product of 8 distinct numbers.

first we can write 3*3=9 and also take -ve of each repeated numbers

that is 2700=2*-2*3*-9*5*-5*1*-1

so this the first method.

second way is

2700=2*-2*9*-3*5*-5*1*-1

this the only way we can express 2700 in the form of product of 8 distinct integers