How many ways can a four digit number be formed with distinct digits?
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no of destiny digits are 10 i.e. 1,2,3,4,5,6,7,8,9,0
let be there are four blanks
in first blank if you keep 0 then it becomes 3 digit number
so no. of chances in first blank is 9!
in 2nd blank no. of chances are 10!
in 3rd blank no. of chances are 10!
in 4th blank no. of chances are 10!
so no. of chances to fill the four blanks are 9!*10!*10!*10!
=9!*(10!)^4
hope this answer helps you dear
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let be there are four blanks
in first blank if you keep 0 then it becomes 3 digit number
so no. of chances in first blank is 9!
in 2nd blank no. of chances are 10!
in 3rd blank no. of chances are 10!
in 4th blank no. of chances are 10!
so no. of chances to fill the four blanks are 9!*10!*10!*10!
=9!*(10!)^4
hope this answer helps you dear
Pls mark as BRAINLIST
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