How many ways can the digit 2 3 5 7 9 be placed to form a 3 digit num?
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Step-by-step explanation:
No of places are 3
No of digits are 5 (2,3,5,7,9)
The first place has 5 options (2,3,5,7,9) === > 5
Second place has 4 options because one digit is already fixed in 1st place ===> 4
Third place has 3 options ( 2 digits are fixed in 1st and 2 nd place) ==> 3
So total number of ways = 5*4*3 === 60
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