Question

How many whole numbers are less than n+1?

Answer 1

Answer:

the answer of this question is 0

Answer 2

Answer:

For $n \epsilon N$\{$n-1$}, the no. of whole numbers less than $n+1$ are $n$.

Step-by-step explanation:

Whole numbers: All natural numbers together with $0$ forms the whole numbers. It is denoted by $W$.

Symbolically, $W=N\cup$ {$0$}

Example: $0,\ 1,\ 2,\ . \ . \ .$.

Given: $n+1$

To find: No. of whole numbers less than $n+1$.

As we know that the smallest whole number is $0$.

⇒ $0 < n+1$ for $n \epsilon N$

For whole number $1$,

⇒ $1 < n+1$ for $n \epsilon N$

For whole number $2$,

⇒ $2 < n+1$ for $n \epsilon N$\{$1$}

For whole number $3$,

⇒ $3 < n+1$ for $n \epsilon N$\{$2$}

Likewise, we get

$n$ whole numbers for $n \epsilon N$\{$n-1$}

Therefore, the no. of whole numbers less than $n+1$ are $n$ for $n \epsilon N$\{$n-1$}.

#SPJ2